Submission #10045073


Source Code Expand

#include <iostream>
#include <algorithm>
#include <vector>
#define rep(i,n) for(int i=0;i<n;++i)
#define rep1(i,n) for(int i=1;i<=n;++i)
using namespace std;
typedef long long ll;
const ll MOD=1e+9+7;
struct mint{
  ll x;
  mint(ll x=0):x(x%MOD){}
  mint& operator+=(const mint a){
    if((x+=a.x)>=MOD) x-=MOD;
    return *this;
  }
  mint& operator-=(const mint a){
    if((x += MOD-a.x)>=MOD) x-=MOD;
    return *this;
  }
  mint& operator*=(const mint a){
    (x*=a.x)%=MOD;
    return *this;
  }
  mint operator+(const mint a) const{
    mint res(*this);
    return res+=a;
  }
  mint operator-(const mint a) const{
    mint res(*this);
    return res-=a;
  }
  mint operator*(const mint a) const{
    mint res(*this);
    return res*=a;
  }
  mint pow(ll t) const{
    if(!t) return 1;
    mint a = pow(t>>1);
    a*=a;
    if(t&1) a*=*this;
    return a;
  }
  
  //for prime mod
  mint inv() const{
    return pow(MOD-2);
  }
  mint& operator/=(const mint a){
    return (*this) *= a.inv();
  }
  mint operator/(const mint a) const{
    mint res(*this);
    return res/=a;
  }
};

int main()
{
  int t;
  cin >> t;
  vector<int> a(t);
  rep(i,t){
    cin >> a[i];
  }

  vector<vector<mint>> dp(t+1,vector<mint>(601));
  rep(i,t){
    rep(j,a[i]+1){
      dp[i][j].x = 1;
    }
  }

  rep1(i,t-1){
    rep1(j,601){
      rep(k,a[i]+1){
	if(j%2==0){
	  dp[i][j/2+k] += dp[i-1][j];
	}
      }
    }
  }

  mint res;
  rep(i,t){
    res += dp[i][1];
  }

  int x = 2;
  while(x<=600){
    res += dp[t-1][x];
    x *= 2;
  }

  cout << res.x << "\n";
  
  return 0;
}

Submission Info

Submission Time
Task E - Union
User kkktym
Language C++14 (GCC 5.4.1)
Score 400
Code Size 1669 Byte
Status AC
Exec Time 87 ms
Memory 1664 KB

Judge Result

Set Name Sample All
Score / Max Score 0 / 0 400 / 400
Status
AC × 3
AC × 33
Set Name Test Cases
Sample s1.txt, s2.txt, s3.txt
All 01.txt, 02.txt, 03.txt, 04.txt, 05.txt, 06.txt, 07.txt, 08.txt, 09.txt, 10.txt, 11.txt, 12.txt, 13.txt, 14.txt, 15.txt, 16.txt, 17.txt, 18.txt, 19.txt, 20.txt, 21.txt, 22.txt, 23.txt, 24.txt, 25.txt, 26.txt, 27.txt, 28.txt, 29.txt, 30.txt, s1.txt, s2.txt, s3.txt
Case Name Status Exec Time Memory
01.txt AC 1 ms 256 KB
02.txt AC 1 ms 256 KB
03.txt AC 1 ms 256 KB
04.txt AC 1 ms 256 KB
05.txt AC 1 ms 256 KB
06.txt AC 5 ms 768 KB
07.txt AC 5 ms 640 KB
08.txt AC 5 ms 768 KB
09.txt AC 5 ms 768 KB
10.txt AC 5 ms 768 KB
11.txt AC 35 ms 1664 KB
12.txt AC 36 ms 1664 KB
13.txt AC 35 ms 1664 KB
14.txt AC 34 ms 1664 KB
15.txt AC 35 ms 1664 KB
16.txt AC 85 ms 1664 KB
17.txt AC 85 ms 1664 KB
18.txt AC 86 ms 1664 KB
19.txt AC 84 ms 1664 KB
20.txt AC 87 ms 1664 KB
21.txt AC 87 ms 1664 KB
22.txt AC 85 ms 1664 KB
23.txt AC 87 ms 1664 KB
24.txt AC 85 ms 1664 KB
25.txt AC 86 ms 1664 KB
26.txt AC 86 ms 1664 KB
27.txt AC 2 ms 640 KB
28.txt AC 1 ms 512 KB
29.txt AC 2 ms 768 KB
30.txt AC 2 ms 768 KB
s1.txt AC 1 ms 256 KB
s2.txt AC 1 ms 256 KB
s3.txt AC 3 ms 256 KB